In the lab, Michelle and Brian measured the acceleration of a cart rolling on an inclined track with one block under one end, and found that the acceleration was 0.482 m/s2. On another table, Yasin and Cameron found, with a similar setup, an acceleration of 0.718 m/s2. a. What is the percent difference between the result found by Yasin and Cameron, aY&C, in terms of the result of Michelle and Brian, aM&B? b. What is the percent difference between the two results when you treat them as "equivalent"?

Question

Koen Roy

Physics

7 September, 20:07

In the lab, Michelle and Brian measured the acceleration of a cart rolling on an inclined track with one block under one end, and found that the acceleration was 0.482 m/s2. On another table, Yasin and Cameron found, with a similar setup, an acceleration of 0.718 m/s2. a. What is the percent difference between the result found by Yasin and Cameron, aY&C, in terms of the result of Michelle and Brian, aM&B? b. What is the percent difference between the two results when you treat them as "equivalent"?

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Answers (1)

Know the Answer?

Rose Rice · Answer 1

a) e% = 49.0%

, b) e% = 19.7%

Explanation:

The percentage difference is the absolute uncertainty between the value accepted by 100

e% = Δx / x_value

a) for this case the correct accepted value is x_value = 0.482 m / s²

Δx = 0.718 - 0.482

Δx = 0.236 m / s²

e% = 0.236 / 0.482 100

e% = 48.96%

b) In this case the results of the two experiments are real and the correct value is the average

x_value = (0.482 + 0.718) / 2

x_value = 0.600 m / s²

e% = (0.718 - 0.600) / 0.600 100

e% = 19.7%