A man stands on a scale in an elevator as shown here. the force of his weight when the elevator is still is fg downward. suppose the elevator's acceleration downward is 1/4 g. the weight of the man, fs, is what

Question

Aliana Mckenzie

Physics

27 January, 03:24

A man stands on a scale in an elevator as shown here. the force of his weight when the elevator is still is fg downward. suppose the elevator's acceleration downward is 1/4 g. the weight of the man, fs, is what

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Answers (1)

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Erika Kidd · Answer 1

When the elevator moves downward, the man weighs less because of the inertia.

Force of Weight:Fg=m*g

Fs=m*g-m*1/4g=m * (g-1/4g) = m*3/4g

If He Went Up you would have to add 1/4g