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16 December, 05:15

A 9000-N automobile is pushed along a level road by four studentswho apply a total forwardforce of 500 N. Neglecting friction, the acceleration of theautomobile is:

A. 0.055m/s2B. 0.54m/s2C. 1.8m/s2D. 9.8m/s2E. 18m/s2

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  1. 16 December, 05:26
    0
    B. 0.54 m/s²

    Explanation:

    Acceleration: This can be defined as the rate of change of velocity. The S. I unit of acceleration is m/s².

    From Newton's fundamental equation,

    F = ma ... Equation 1

    Where F = force applied on the automobile, m = mass of the automobile, a = acceleration of the automobile.

    Making a the subject of the equation,

    a = F/m ... Equation 2

    But,

    W = mg ... Equation 3

    Where W = weight of the automobile, g = acceleration due to gravity.

    Given: W = 9000 N, g = 9.8 m/s²

    Substitute into equation 3

    9000 = 9.81m

    m = 9000/9.81

    m = 917.43 kg.

    Also given: F = 500 N. and m = 917.43 kg

    Substitute into equation 2,

    a = 500/917.43

    a = 0.54 m/s²

    Hence the acceleration of the automobile = 0.54 m/s²

    The right option is B. 0.54 m/s²
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