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30 March, 02:18

An object with a mass of 500 kg is dropped from a tall crane. After having fallen 70 % of the total distance to the ground, the object has a potential energy of 44100 joules. What is its kinetic energy at this time?

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  1. 30 March, 02:37
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    102900 Joules

    Explanation:

    Assuming the kinetic energy was zero at the moment of release, you can make the following argument to solve the problem:

    The potential energy at full height was mgh. We are told that after 70% of the distance, i. e., mg (0.3h) = 44.1kJ. Since potential energy is linear in altitude h, we get get the full potential energy to be 44.1kJ/0.3. The difference between full potential energy and the one after 70% of the way must equal the gained kinetic energy (neglecting stuff like heat due to friction). So,

    44.1kJ/0.3 - 44.1kJ = 0.7*44.1kJ/0.3 = 102.9kJ = Ekinetic

    The kinetic energy after 70% of the falling distance was 102.9 kJ.
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