A small airplane with a wingspan of 18.0 m is flying due north at a speed of 63.6 m/s over a region where the vertical component of the Earth's magnetic field is 1.20 µT downward. What potential difference is developed between the airplane's wingtips and which wingtip is at higher potential?

Question

Cash Joseph

Physics

31 March, 08:27

A small airplane with a wingspan of 18.0 m is flying due north at a speed of 63.6 m/s over a region where the vertical component of the Earth's magnetic field is 1.20 µT downward. What potential difference is developed between the airplane's wingtips and which wingtip is at higher potential?

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Answers (1)

Know the Answer?

Fiona Clark · Answer 1

(a) ε = 1373.8.

(b) The wingtip which is at higher potential.

Explanation:

(a) Finding the potential difference between the airplane wingtips.

Given the parameters

wingspan of the plane is = 18.0m

speed of the plane in north direction is = 70.0m/s

magnetic field of the earth is = 1.20μT

The potential difference is given as:

ε = Blv

where ε = potential difference of wingtips

B = magnetic field of earth

l = wingspan of airplane

v = speed of airplane

ε = 1.2 x 18.0 x 63.6

ε = 1373.8

(b) Which wingtip is at higher potential?

The wingtip which is at higher potential.