A silver bar has a mass of 260.0 g and is heated from 22.0 °C to 70.0 °C. How much heat does the silver bar absorb? Silver has a specific heat of 0.235 J / (g °C).

By Energy = mass * specific heat capacity * temperature change,

260 * 0.235 * (70 - 22) = 2932.8 J

The answer is 2,932.8 J

Explanation:

The formula for heat gained = MC (T2 - T1)

Where, given values are:

M = mass of silver bar = 260g

C = specific heat capacity of silver = 0.235 J / (g °C)

T2 = final temperature = 70.0 °C

T1 = initial temperature = 22.0 °C

Therefore, heat gained = 260 * 0.235 * (70.0 - 22.0) = 2,932.8 J