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8 August, 19:41

An object at the surface of the Earth (thus, a distance R from the center of the Earth) weighs 180 N. Its weight at a distance 3R from the center of the Earth is:

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  1. 8 August, 19:54
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    Answer: 20N

    Explanation:

    According to Newton's law of gravitation which states that every particle attracts every other particle in the universe with a force which is directly proportional to the product of their masses and inversely proportional to the square of the distance between their centers

    F = Gm1m2/r^2

    Where

    F = force between the masses

    G universal gravitational constant

    m1 and m2 = mass of the two particles

    r = distance between the centre of the two mass

    Therefore, weigh of an object on earth is inversely proportional to the square of its distance from the centre of the earth

    W₁/W₂ = r₂²/r₁²

    W₂ = W₁r₁²/r₂²

    W₁ = 180 N

    r₁ = R

    r₂ = 3R

    W₂ = (180 * R²) / (3R) ²

    W₂ = 180R²/9R²

    W₂ = 180/9

    W₂ = 20N

    its weight at 3R is 20N
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