Ask Question
14 March, 19:45

A (n) 26000 kg freight car is rolling along a track at 3.3 m/s. Calculate the time needed for a force of 1150 N to stop the car. Answer in units of s.

+3
Answers (1)
  1. 14 March, 19:55
    0
    The time = 74.61 s.

    Explanation:

    From Newton's Third law of motion,

    The force needed to stop is equal and opposite to the propelling force from the engine of the freight car.

    F = ma ... Equation 1

    Where F = force needed to stop the the freight car, m = mass of the freight car, a = acceleration of the freight car.

    a = F/m ... Equation 2.

    Given: F = - 1150 N (Opposite in direction to the motion of the car) m = 26000 kg.

    Substituting into equation 2

    a = - 1150/26000

    a = - 0.04423 m/s²

    Also

    v = u + at

    t = (v-u) / a ... Equation 3

    Where t = time needed for the force to stop the car, v = final velocity, u = initial velocity, a = acceleration.

    Given: u = 3.3 m/s v = 0 m/s (brought to rest), a = - 0.04423 m/s²

    Substituting into equation 3

    t = (0-3.3) / -0.04423

    t = - 3.3/0.04423

    t = 74.61 sec.

    Thus the time = 74.61 s
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “A (n) 26000 kg freight car is rolling along a track at 3.3 m/s. Calculate the time needed for a force of 1150 N to stop the car. Answer in ...” in 📗 Physics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers