A shot-putter throws the shot with an initial speed of 15.5m/s at a 34 degree angle to the horizontal. calculate the horizontal distance traveled by the shot if it leaves the athlete's hand at a height of 2.20m above the ground.

Question

Darwin Lee

Physics

18 July, 23:11

A shot-putter throws the shot with an initial speed of 15.5m/s at a 34 degree angle to the horizontal. calculate the horizontal distance traveled by the shot if it leaves the athlete's hand at a height of 2.20m above the ground.

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Moses Sellers · Answer 1

This can be solve by using the formula

x = (v^2) (sin 2a) / gwhere v is the intial velocitya is the angle of trajectoryg is the acceleration due to gravity (9.8 m/s2)

x = (15.5^2) (sin 2 (34) / 9.8x = 22.73 m