Siska hit a golf ball into the air with an initial velocity of 56 feet per second. The height h in feet of the ball above the ground can be modeled by h=-16t^{2}+56t, where t is the time in seconds after Sisika hit the ball. Find the time it takes the ball to reach 49 feet above the ground.

Question

Dereon Palmer

Physics

6 October, 11:45

Siska hit a golf ball into the air with an initial velocity of 56 feet per second. The height h in feet of the ball above the ground can be modeled by h=-16t^{2}+56t, where t is the time in seconds after Sisika hit the ball. Find the time it takes the ball to reach 49 feet above the ground.

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Kadyn Pace · Answer 1

To find the time it takes for the ball to reach the given height, we need an equation that relates the height and time it travel which is given to be h=-16t^{2}+56t. We just substitute the height of 49 feet then solve for t. We do as follows:

h=-16t^{2}+56t

49 = - 16t^{2}+56t

t = 1.75 seconds

Hope this answers the question. Have a nice day.