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15 June, 00:44

As a tennis ball is struck, it departs from the racket horizontally with a speed of 28.0 m/s. The ball hits the court at a horizontal distance of 19.6 m from the racket. How far above the court is the tennis ball when it leaves the racket?

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  1. 15 June, 01:12
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    solution:

    long to travel 19.6m at 28m/s

    t = 19.6/28

    =time taken to drop from rest

    s=ut + (1/2) at^2

    u=0

    a=~10

    so s = (1/2) * 10 * (19.6/28) ^2 = 2.45m
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