Your outlets at home are rated at 120 V, i. e. the two prongs have on average a potential difference of 120V. If you transfer 2.7 moles of electrons at that voltage, how much energy is released?

E = 230.4 MJ

Explanation:

As 1 mole of electron = 6X 10^23 particles.

charge of an electron is 1.6 X 10 ^-19 C

Finding Charge:

(6X10^23) (2.7) (1.6X10^-19 C)

i. e. 192 K C

now to find the energy released from electrons

V=E/q

E=V X q

i. e E = 120 V X 192 K C

E = 230.4 MJ