a runner moves 2.38 m/s north. She accelerates at 0.310 m/s^2 at a - 62.0 degree angle. How many seconds later is she running directly east

Question

Marlee Heath

Physics

16 June, 06:02

a runner moves 2.38 m/s north. She accelerates at 0.310 m/s^2 at a - 62.0 degree angle. How many seconds later is she running directly east

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Answers (1)

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Trevin Garcia · Answer 1

8.70 s

Explanation:

Given (in the y direction):

v₀ = 2.38 m/s

v = 0 m/s

a = 0.310 sin (-62.0°) m/s²

Find: t

v = at + v₀

0 m/s = (0.310 sin (-62.0°) m/s²) t + (2.38 m/s)

t = 8.70 s