A pendulum bob is released from some initial height such that the speed of the bob at the bottom of the swing is 2.7 m/s. The acceleration of gravity is 9.81 m/s^2.

What is the initial height of the bob? Answer in units of m.

Question

Rachael Patrick

Physics

22 September, 02:59

A pendulum bob is released from some initial height such that the speed of the bob at the bottom of the swing is 2.7 m/s. The acceleration of gravity is 9.81 m/s^2.

What is the initial height of the bob? Answer in units of m.

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Answers (1)

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Ada Solis · Answer 1

v squared equals 2gh so the answer gives 2.7*2.7 = 2*9.81*h the answer for the math solution of the speed of the bob at the bottom of the swing being 2.7 is 0.396 meters

A pendulum bob is released from some initial height such that the speed of the bob at the bottom of the swing is 2.7 m/s. The acceleration of gravity is 9.81 m/s^2.What is the initial height of the bob? Answer in units of m.

A pendulum bob is released from some initial height such that the speed of the bob at the bottom of the swing is 2.7 m/s. The acceleration of gravity is 9.81 m/s^2.

What is the initial height of the bob? Answer in units of m.