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13 June, 20:31

A tourist being chased by an angry bear is running in a straight line toward his car at a speed of 3.60 m/s. The car is a distance d away. The bear is 39.3 m behind the tourist and running at 5.00 m/s. The tourist reaches the car safely. What is the maximum possible value for d

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  1. 13 June, 20:53
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    101 meters

    Explanation:

    Distance traveled by the tourist:

    d = 3.60 m/s * t

    Distance traveled by the bear:

    d + 39.3 m = 5.00 m/s * t

    Substitute:

    3.6 t + 39.3 = 5 t

    39.3 = 1.4 t

    t = 28.1

    d = 101
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