Runner whose weight is 800 N wishes to accelerate at 5m/s^2 what minimum coefficient of friction is required for her to accelerate without slipping?

A) 0.25

B) 0.50

C) 0.30

D) 0.40

Question

Catalina

Physics

26 January, 18:40

Runner whose weight is 800 N wishes to accelerate at 5m/s^2 what minimum coefficient of friction is required for her to accelerate without slipping?

A) 0.25

B) 0.50

C) 0.30

D) 0.40

+4

Answers (1)

Know the Answer?

Yuliana Ramsey · Answer 1

B) 0.50

Explanation:

Draw a free body diagram. There are three forces: weight force mg down, normal force N up, and friction force Nμ forward.

Sum of forces in the y direction:

∑F = ma

N - mg = 0

N = mg

Sum of forces in the x direction:

∑F = ma

Nμ = ma

mgμ = ma

gμ = a

μ = a / g

μ = (5 m/s²) / (10 m/s²)

μ = 0.50

Runner whose weight is 800 N wishes to accelerate at 5m/s^2 what minimum coefficient of friction is required for her to accelerate without slipping?A) 0.25B) 0.50C) 0.30D) 0.40

Runner whose weight is 800 N wishes to accelerate at 5m/s^2 what minimum coefficient of friction is required for her to accelerate without slipping?

A) 0.25

B) 0.50

C) 0.30

D) 0.40