Find the electric flux (in N m2/c) through a rectangular area 5.0 cm x 4.0 cm between two charged parallel plates where there is a constant electric field of 27 N/C for the following orientations of the area. (Enter the magnitudes.) (a) parallel to the plates N m2/c N m2/c N m2/c (b) perpendicular to the plates (c) the normal to the area making a 30 angle with the direction of the electric field; note that this angle can also be given as 180 30

Question

Andre Bernard

Physics

6 September, 20:34

Find the electric flux (in N m2/c) through a rectangular area 5.0 cm x 4.0 cm between two charged parallel plates where there is a constant electric field of 27 N/C for the following orientations of the area. (Enter the magnitudes.) (a) parallel to the plates N m2/c N m2/c N m2/c (b) perpendicular to the plates (c) the normal to the area making a 30 angle with the direction of the electric field; note that this angle can also be given as 180 30

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Answers (1)

Know the Answer?

Alfredo Hammond · Answer 1

a) 0.054 N m²/C

b) 0

c) 0.0467 N m²/C

Explanation:

a) Electric flux = Φ = E A cos θ

E = Electric field = 27 N/C

Area = A = 0.05*0.04 = 0.002 m²

Angle = θ = 0, since they are parallel.

Φ = Electric flux = (27) (0.002) (cos 0) = 0.054 N m²/C

b) When θ = 90°, perpendicular

Ф = Electric flux = (27) (0.002) (cos 90) = 0

c) θ = 30 degrees,

Φ = Electric flux = (27) (0.002) (cos 30) = 0.0467 N m²/C