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20 March, 08:59

A spring has a equilibrium length of 10.0 cm. When a force of 40.0 N is applied to the spring, the spring has a length of 14.0 cm. What is the value of the spring constant of this spring?

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  1. 20 March, 09:12
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    The value of the spring constant of this spring is 1000 N/m

    Explanation:

    Given;

    equilibrium length of the spring, L = 10.0 cm

    new length of the spring, L₀ = 14 cm

    applied force on the spring, F = 40 N

    extension of the spring due to applied force, e = L₀ - L = 14 cm - 10 cm = 4 cm

    From Hook's law

    Force applied to a spring is directly proportional to the extension produced, provided the elastic limit is not exceeded.

    F ∝ e

    F = ke

    where;

    k is the spring constant

    k = F / e

    k = 40 / 0.04

    k = 1000 N/m

    Therefore, the value of the spring constant of this spring is 1000 N/m
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