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21 July, 20:52

When light bulbs A and B are connected in series to a battery, A glows brightly and B glows dimly. You remove bulb B so that the circuit is just the battery and bulb A and connect bulb B to an identical battery. With the two bulbs connected to identical batteries but in separate circuits, do they glow equally brightly now? a. Bulb A glows brighter b. The two bulbs glow equally brighty. c. Bulb B glows brighter.

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  1. 21 July, 20:54
    0
    When the two bulbs A and B are connected in series, the current is same in both the bulbs. Power is given by

    P = i²R

    so, as the bulb A is glowing more than the B, so the resistance of A is more than B.

    Now they are connected seperately by two indentical batteries. The potential difference is same in both the bulbs.

    Power is given by

    P = V²/R

    as the resistance of B is smaller than the resistance of A, so the brightness of bulb B is more than A.
  2. 21 July, 20:58
    0
    The bulb B glows brighter.

    Explanation:

    Given that,

    A glows brightly and B glows dimly.

    According to ohm's law,

    Two light bulbs A and B are connected in series to a battery then the current will be same in both bulbs and the resistance is high of bulb A and low in bulb B.

    If bulb A connect to a battery and bulb B connect to a same battery separately.

    Then bulb B glows brighter because the resistance is high in bulb A so the current will be low.

    The resistance is low in bulb B so the current will be high.

    Hence, The bulb B glows brighter.
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