A simple pendulum has a period of 1.0 s. If you take this pendulum to Mars where the acceleration of gravity is 3.8 m/s2, what will the period of the pendulum be

The period of the simple pendulum in mars = 1.60 s

Explanation:

Period: The period of a simple pendulum is the time taken in seconds for the pendulum to complete one oscillation.

The period of a simple pendulum is

T = 2π√ (L/g) ... Equation 1

making L the subject of the equation above,

L = T²g/4π² ... Equation 2

Where T = period of simple pendulum, L = length of the pendulum, g = acceleration due to gravity.

Given: T = 1.0 s,

Constant: g = 9.8 m/s², π = 3.143

Substituting these values into equation 2

L = (1²*9.8) / (4*3.143²)

L = 9.8/39.51

L = 0.248 m.

If the pendulum is taken to mars, of acceleration due to gravity = 3.8 m/s²

T = 2*3.143√ (0.248/3.8)

T = 6.286√0.0653

T = 6.286*0.256

T = 1.60 s

Therefore the period of the simple pendulum in mars = 1.60 s