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10 December, 06:51

Two forces whose resultant is 100N, are perpendicular to each other. if one of them makes an angle of 60° with the resultant, calculate it's magnitude

Calculate the absolute pressure of an ocean depth of 1200atm. Assuming the density of liquid is 1200kg/m^2amd that (pa=1.01*10^6pa N/m^2

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  1. 10 December, 07:03
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    Magnitude of the force = 50N

    Explanation:

    Let one force be X

    And the second force be Y

    Both the forces are perpendicular, so α = 90°

    The resultant R of the two forces = 100N

    Angle between resultant and 1 force, α = 60°

    We know,

    R² = X² + Y² + 2XYcos 90

    100² = X² + Y²

    If X makes an angle of Φ = 60°

    Then, tan Ф = Y sin α / X + Y cos α

    Putting the values we find,

    tan 60 = Y/X

    Y = √3X

    Putting Y = √3X in equation 1 we get,

    (X) ² + (√3X) ² = 100 X 100

    4X² = 100 X 100

    X² = 2500

    X = 50N

    Therefore, magnitude of the force = 50N
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