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15 February, 18:39

A horizontal wire 1 m long carries 0.4 A and is oriented 30° N of W. The Earth's magnetic field runs due north at this location and is 1.5 x 10^-5 T in strength. What is the magnitude and direction of the magnetic force on the wire?

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  1. 15 February, 19:01
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    Force on a current carrying conductor in a magnetic field is given by the following expression

    F = B i L where B is magnetic field perpendicular to wire or current, i is current and L is length of the wire.

    Magnetic field of 1.5 x 10⁻⁵ T is making an angle of 60 degree with the wire so the component of field perpendicular to it

    B = 1.5 X 10⁻⁵ Cos 30° = 1.3 x 10⁻⁵ T.

    Force = BiL

    = 1.3 X 10⁻⁵ X. 4 X 1

    = 5.2 X 10⁻⁶ N.

    The direction of force can be found out from Fleming's left hand rule. It will be along downward direction.
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