Ask Question
26 May, 15:57

A 3.0-kg cart is rolling across a frictionless, horizontal track toward a 1.3-kg cart that is held initially at rest. The carts are loaded with strong magnets that cause them to attract one another. Thus, the speed of each cart increases. At a certain instant before the carts collide, the first cart's velocity is + 4.6 m/s, and the second cart's velocity is - 1.9 m/s.

(Indicate the direction with the sign of your answer.)

(a) What is the total momentum of the system of the two carts at this instant?

kg · m/s

(b) What was the velocity of the first cart when the second cart was still at rest?

m/s

+2
Answers (1)
  1. 26 May, 16:04
    0
    a) Momentum of first cart = mass x velocity

    = 3 x 4.6 = + 13.8 kg m / s

    Momentum of second cart = 1.3 x - 1.9 = - 2.47 kg m / s

    Total momentum = 13.8 - 2.47

    = + 11.33 kg m / s

    b)

    Let the velocity of first cart be v at the moment when second cart was at rest

    total momentum = 3 x v + 0 = 3 v

    Applying conservation of momentum law

    3 v = + 11.33

    v = + 3.77 m / s
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “A 3.0-kg cart is rolling across a frictionless, horizontal track toward a 1.3-kg cart that is held initially at rest. The carts are loaded ...” in 📗 Physics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers