The Hubble telescope's orbit is 5.6 x 105 meters above Earth's surface. The telescope has a mass of 1.1 x 104 kilograms. Earth exerts a gravitational force of 9.1 x 104 newtons on the telescope. What is the magnitude of Earth's gravitational field strength at this location?

F=Gm1m2/r^2where:

F is the force between the masses; G is the gravitational constant (N · (m/kg) 2); m1 is the first mass; m2 is the second mass; r is the distance between the centers of the masses.

m1 = mass earth = 5.972 * 10^24 kg

9.1 x 10^4 N = G (5.972 * 10^24 kg) (1.1 x 10^4 kg) / (5.6 x 10^5 m) ^2 solve for GG = 4.34x10^-13 N · (m/kg) 2