A rubber ball with a mass 0.20 kg is dropped vertically from a height of 1.5 m above the floor. The ball bounces off of the floor, and during the bounce 0.60 J of energy is dissipated. What is the maximum height of the ball after the bounce?

Potential Energy = mass * Hight * acceleration of gravity

PE=hmg

PE = 1.5 *.2 * 9.81

PE = 2.943

it lost. 6 so 2.943 -.6 = 2.343

now your new energy is 2.343 so solve for height

2.343 = mhg

2.334 =.2 * h * 9.81

h = 1.194

the ball after the bounce only went up 1.194m