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14 January, 02:05

A 18.0 kg child descends a slide 3.40 m high and reaches the bottom with a speed of 2.48 m/s. How much thermal energy due to friction was generated in this process?

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  1. 14 January, 02:09
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    544 J

    Explanation:

    Potential energy at top = kinetic energy at bottom + work done by friction

    PE = KE + W

    mgh = ½ mv² + W

    W = mgh - ½ mv²

    Given m = 18.0 kg, h = 3.40 m, and v = 2.48 m/s:

    W = (18.0 kg) (9.8 m/s²) (3.40 m) - ½ (18.0 kg) (2.48 m/s) ²

    W = 544 J
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