What is the magnetic force (in newtons) on a particle traveling in a 1.5 T magnetic field if q = 7.5 microcoulombs and v = 1.75 * 106 m/s at a 45° angle to the magnetic field? Answer with three signficant digits.

Question

Yesenia Wallace

Physics

16 September, 04:24

What is the magnetic force (in newtons) on a particle traveling in a 1.5 T magnetic field if q = 7.5 microcoulombs and v = 1.75 * 106 m/s at a 45° angle to the magnetic field? Answer with three signficant digits.

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Answers (1)

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Amare Harrington · Answer 1

Given:

B (Magnetic field) : 1.5 T

q = 7.5 microcoulombs

v = 1.75 x 10 ∧6 m/s

The angle ∅ between B and v is 45 °.

Now we know that F = qvB sin ∅

Substituting these values we get:

F = 7.5 x 10∧-6 x 1.75 x 10∧6 x 1.5 x sin 45

F = 16.752 N