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21 November, 15:30

Find the orbital period (in years) of an asteroid whose average distance from the sun is 27

a. u. only enter the number, not the units

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  1. 21 November, 15:58
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    Using Kepler's third law which is defined as the square of the average distance is directly proportional to the cube of the period. It is expressed as P^2 = a^3, Given that the a = average distance is given, the period would be much easier to compute. P = sqrt (27^3) = 140
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