Two lightbulbs each with a resistance of 20 Ω are connected in series to a voltage of 120 V. If a third lightbulb of 20 Ω is added to the circuit, how will the current change?

A. It will remain the same.

B. It will increase from 40 A to 60 A.

C. It will decrease from 30 A to 20 A.

D. It will decrease from 60 A to 20 A.

Question

Caprice

Physics

5 November, 15:59

Two lightbulbs each with a resistance of 20 Ω are connected in series to a voltage of 120 V. If a third lightbulb of 20 Ω is added to the circuit, how will the current change?

A. It will remain the same.

B. It will increase from 40 A to 60 A.

C. It will decrease from 30 A to 20 A.

D. It will decrease from 60 A to 20 A.

+5

Answers (1)

Know the Answer?

Jairo Smith · Answer 1

Total resistance = 20 + 20=40Ω

Voltage=120v

Current = voltage/resistance = 30A

After adding another bulb:

Total resistance = 20 + 20 + 20 = 60Ω

Voltage=120v

Current=120/60 = 20A

Answer is option C