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7 April, 00:54

1. A 1 kg hockey puck is moving at 10 m/s across the ice. At the other end of the ice rink, its speed is measured at 9.2 m/s. If the puck traveled 60

m, how much friction force acted on the puck? (assume the friction force was constant the whole time).

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Answers (1)
  1. 7 April, 01:07
    0
    0.128 N

    Explanation:

    ½ mv²initial = ½ mv²final + Ff d

    ½ (1) (10²) = ½ (1) (9.2²) + (Ff) (60)

    50 = 43.32 + (Ff) (60)

    7.68 = (Ff) (60)

    0.128 = Ff

    Note:

    Ff - force of friction
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