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18 December, 14:56

You give a crate a push to set it in motion. After the push is over, the crate skids to a stop on a rough, level floor. Describe the energy changes after the push (with the crate as the system).

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Answers (2)
  1. 18 December, 15:06
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    Answer: potential to kinetic and then potential energies
  2. 18 December, 15:18
    0
    KE₁ = PE₂

    Explanation:

    From the principle of conservation of energy we know that

    KE₁ + PE₁ = KE₂ + PE₂

    where KE is the kinetic energy and PE is potential energy

    KE = ½mv²

    PE = mgd

    Initially, you gave a push to crate and it started moving with some velocity

    KE₁ = ½mv₁²

    Initially, the potential energy is zero since it didnt cover any distance

    PE₁ = mgd₁ = 0

    At the final state, the crate stopped and its finally velocity become zero, therefore, the kinetic energy is zero.

    KE₂ = ½mv₂² = 0

    At the final state, the crate covered some distance and the final potential energy is

    PE₂ = mgd₂

    Therefore, the energy relation becomes

    KE₁ + PE₁ = KE₂ + PE₂

    KE₁ + 0 = 0 + PE₂

    KE₁ = PE₂

    Hence, the initial kinetic energy of the system is converted to final potential energy of the system.
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