1. You throw a ball from a window at a velocity of 2 m/s downward. How fast will the ball be

moving when it hits the sidewalk 2.5 m below?

Question

Jamie

Physics

6 November, 10:31

1. You throw a ball from a window at a velocity of 2 m/s downward. How fast will the ball be

moving when it hits the sidewalk 2.5 m below?

+5

Answers (1)

Know the Answer?

Alfred Young · Answer 1

Initial velocity (u) = 2 m/s

Displacement (s) = 2.5 m

Acceleration due to gravity (a) = 9.81m/s^2

Final velocity (v) = ?

Now, formula is given by

v² = u² + 2*a*s

v² = 2² + 2*9.81*2.5

v² = 4 + 49.05

v² = 53.05

v = √53.05

v = 7.3 m/s

1. You throw a ball from a window at a velocity of 2 m/s downward. How fast will the ball bemoving when it hits the sidewalk 2.5 m below?

1. You throw a ball from a window at a velocity of 2 m/s downward. How fast will the ball be

moving when it hits the sidewalk 2.5 m below?