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26 January, 16:39

Water flows through a pipe of

radius 0.0250 m at 1.50 m/s.

The pipe narrows to a radius of

0.0100 m. What is the new

velocity of the water?

(Unit = m/s)

+4
Answers (1)
  1. 26 January, 16:43
    0
    9.38 m/s

    Explanation:

    Mass is conserved.

    m₁ = m₂

    ρ₁ Q₁ = ρ₂ Q₂

    Assuming no change in density:

    Q₁ = Q₂

    v₁ A₁ = v₂ A₂

    v₁ π r₁² = v₂ π r₂²

    v₁ r₁² = v₂ r₂²

    Plugging in values:

    (1.50 m/s) (0.0250 m) ² = v (0.0100 m) ²

    v = 9.38 m/s
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