In an isolated system bicyclist 1 and bicyclist 2 each with a mass of 80 kg, collide. bicyclist 1 was moving to the right at 8 m/s, while bicyclist 2 was moving to the left at 2 m/s. what is the magnitude of their combined momentum before the crash

Question

William Moody

Physics

13 July, 08:46

In an isolated system bicyclist 1 and bicyclist 2 each with a mass of 80 kg, collide. bicyclist 1 was moving to the right at 8 m/s, while bicyclist 2 was moving to the left at 2 m/s. what is the magnitude of their combined momentum before the crash

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Gavin Valdez · Answer 1

Consider speed of bicyclist 1 as V1=+8m/s and bicyclist 2 as V2=-2m/s m=80kg

Since momentum has opposite signs moving to right or left

Therefore the combined momentum, P is given by:

P=m*V1+m*V2 = 80 * (8-2) kg*m/s=+480 kg m/s