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8 June, 03:11

In a ballistics test, a 1.50-g bullet is fired through a 28.0-kg block traveling horizontally toward the bullet. In this test, the bullet takes 11.4 ms to pass through the block as it reverses the block's velocity from 1.75 m/s to the right to 1.20 m/s to the left with constant acceleration. Find the magnitude of the force that the bullet exerts on the block during this ballistics test.

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  1. 8 June, 03:19
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    By newtons 3rd law of motion

    Rate of change in momentum of the bullet = Rate of change in momentum of the block

    ForceBullet=Forceblock

    Force∙=mblock∗ (vfinal-vinitial) / t

    ForceBullet=28 (1.20 - (-1.75) / 11.4*10-3
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