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17 April, 10:12

How much work is done to move 1 uC of charge from the negative terminal to the positive terminal of a 1.5V battery?

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  1. 17 April, 11:38
    0
    1.5 x 10⁻⁶ J

    Explanation:

    q = magnitude of charge on the charge = 1 x 10⁻⁶ C

    ΔV = Potential difference between positive and negative terminals of battery = 1.5 Volts

    W = Amount of work done to move the charge from negative terminal to the positive terminal

    Work done is given as

    W = q ΔV

    W = (1 x 10⁻⁶) (1.5)

    W = 1.5 x 10⁻⁶ J
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