A 580-mm long tungsten wire, with a 0.046-mm-diameter circular cross section, is wrapped around in the shape of a coil and used as a filament in an incandescent light bulb. When the light bulb is connected to a battery, a current of 0.526 A is measured through the filament. (Note: tungsten has a resistivity of 4.9 * 10-8 Ω • m.). How many electrons pass through this filament in 5 seconds?

Question

Gianni Brooks

Physics

3 September, 06:20

A 580-mm long tungsten wire, with a 0.046-mm-diameter circular cross section, is wrapped around in the shape of a coil and used as a filament in an incandescent light bulb. When the light bulb is connected to a battery, a current of 0.526 A is measured through the filament. (Note: tungsten has a resistivity of 4.9 * 10-8 Ω • m.). How many electrons pass through this filament in 5 seconds?

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Answers (1)

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Leo Cantu · Answer 1

Answer: 1.64 * 10^19 electrons

Explanation: In order to the explain this problem we have to consider the following:

The current = charge/time; so

as the electrons move in the tungsten wire we have:

0.526 C/s = N electrons per second * charge of electron=

N electrons/s = 0.526/1.6*10^-19 = 3.28 * 10^18 electrons/s

Then, during 5 seconds will pass:

3.28 * 10^18 electrons/s*5 5s = 1.64 * 10^19 electrons