To practice Problem-Solving Strategy 21.1 Conservation of energy in charge interactions. An alpha particle (α), which is the same as a helium-4 nucleus, is momentarily at rest in a region of space occupied by an electric field. The particle then begins to move. Find the speed of the alpha particle after it has moved through a potential difference of - 3.4510-3 V. The charge and the mass of an alpha particle are qα = 3.2010-19 C and mα = 6.68*10-27 kg, respectively.

Question

Octavio Suarez

Physics

29 June, 20:03

To practice Problem-Solving Strategy 21.1 Conservation of energy in charge interactions. An alpha particle (α), which is the same as a helium-4 nucleus, is momentarily at rest in a region of space occupied by an electric field. The particle then begins to move. Find the speed of the alpha particle after it has moved through a potential difference of - 3.4510-3 V. The charge and the mass of an alpha particle are qα = 3.2010-19 C and mα = 6.68*10-27 kg, respectively.

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Cherry · Answer 1

kinetic energy of alpha particle

= Q X V (Q is charge on the particle and V is potential difference)

= 3.2 x 10⁻¹⁹ x 3.45 x 10⁻³

= 11.04 x 10⁻²² J

1/2 m v² = 11.04 x 10⁻²²

1/2 x 6.68 x 10⁻²⁷ x v² = 11.04 x 10⁻²²

v² = 3.305 x 10⁵

v = 5.75 x 10² m / s