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13 June, 09:18

The area vector of a square loop of 5 turns of a conductor each with side length of 0.2 m carrying a current of 2 A is antiparallel to a uniform magnetic field of 50.0 T in which it lies.

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  1. 13 June, 09:43
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    the magnitude and the direction of the total magnetic field is 0.4 Am² antiparallel to the area vector

    Explanation:

    Given that:

    The area vector of a square loop has 5 numbers of turns i. e n = 5

    each with side length = 0.2 m

    Current I = 2 A

    uniform magnetic field = 50.0 T

    Now; the magnitude of the total magnetic field B is calculated as:

    B = IA

    where;

    I = current

    A = area (n * l²)

    B = I (n * l²)

    B = 2 * 5 * 0.2²

    B = 0.4 Am²

    The direction of the magnetic moment is antiparallel to the area vector;

    Hence; the magnitude and the direction of the total magnetic field is 0.4 Am² antiparallel to the area vector
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