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14 June, 01:48

Consider a sign suspended on a boom that is supported by a cable, as shown. What is the proper equation to use for finding the net force in the y direction?

Fnety = (FT) (sin 32°) + Fg

Fnety = (FT) (sin 32°) - Fg

Fnety = (FT) (cos 32°) + Fg

Fnety = (FT) (cos 32°) - F g

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  1. 14 June, 02:01
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    Fnety = (FT) (sin 32°) - Fg Or the answer B, I checked it.
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