A bird travels 1.70 x 10^4 km south then turns around and travels 6.00 x 10^2 north. He then turns around again immediately and flies 1.44 x 10^4 km south. What are the bird's avg. speed and velocity if it completes the trip in 122 days?

Question

Jared Payne

Physics

16 October, 05:49

A bird travels 1.70 x 10^4 km south then turns around and travels 6.00 x 10^2 north. He then turns around again immediately and flies 1.44 x 10^4 km south. What are the bird's avg. speed and velocity if it completes the trip in 122 days?

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Answers (1)

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Tania Andrews · Answer 1

The distance the bird flies is (17,000 + 600 + 14,400) = 32,000 km.

His average speed is (32,000 km) / (122 days) = 262.3 km/day.

The bird ends up (17,000 - 600 + 14,400) = 30,800 km north

from where he started.

His average velocity is (30,800 km) / (122 days) = 252.5 km/day north.