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18 January, 13:07

The triceps muscle in the back of the upper arm extends the forearm. This muscle in a professional boxer exerts a force of 2615 N with an effective perpendicular lever arm of 2.85 cm, producing an angular acceleration of the forearm of 110.0 rad / s2. What is the moment of inertia of the boxer's forearm?

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  1. 18 January, 13:15
    0
    0.68 kg-m²

    Explanation:

    F = Force applied by the muscle = 2615 N

    r = effective perpendicular lever arm = 2.85 cm = 0.0285 m

    α = Angular acceleration of the forearm = 110.0 rad/s²

    I = moment of inertia of the boxer's forearm = ?

    Torque is given as

    τ = I α eq-1

    Torque is also given as

    τ = r F eq-2

    using eq-1 and eq-2

    r F = I α

    (0.0285) (2615) = (110.0) I

    I = 0.68 kg-m²
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