Near San Francisco, where the vertically downward component of the earth's magnetic field is 4.5 x 10-5 T, a car is traveling forward at 19 m/s. The width of the car is 1.9 m. Find the emf induced between the two sides of the car. If positive charge accumulates on the driver's side, the enter the emf as a positive number. If negative charge accumulates on the driver's side, the enter the emf as a negative number.

Question

Kae

Physics

11 October, 01:36

Near San Francisco, where the vertically downward component of the earth's magnetic field is 4.5 x 10-5 T, a car is traveling forward at 19 m/s. The width of the car is 1.9 m. Find the emf induced between the two sides of the car. If positive charge accumulates on the driver's side, the enter the emf as a positive number. If negative charge accumulates on the driver's side, the enter the emf as a negative number.

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Answers (1)

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Melissa Kline · Answer 1

Answer: E = 1.62*10^-3 v

Explanation:

Given

L = 1.9 m

V = 19 m/s

B = 4.5*10^-5 T

Induced emf can be found by using the formula for induced emf in a moving conductor.

e = blv, where

B is the component of the earth's magnetic field.

L is the width of the car in m

V is the velocity of the car in m/s

E is the induced emf in volts.

E = 4.5*10^-5 * 1.9 * 19

E = 1.62*10^-3 v

The drivers side is more positive, so the charge would remain positive