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27 October, 20:29

if a current flowing through a lightbulb is 0.75 ampere and the voltage differences across the lightbulb is 120 volts how much resistance does the lightbulb have

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  1. 27 October, 20:58
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    We have the equation I = V/R (according to ohm's law

    ==> R = V / I

    ==> R = 120/0.75

    ==> R = 160 ohms

    *I is current (unit : ampere)

    *V is voltage different and R is resistance
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