Moustapha jones reaches the bottom of a hill on his bike moving at a speed of 8.6 m/s when his chain breaks. he coasts up the hill until he comes to a stop after 3.5 s. find his acceleration while on the hill, and the distance he travelled up the hill.

Question

Asher Morris

Physics

20 February, 13:27

Moustapha jones reaches the bottom of a hill on his bike moving at a speed of 8.6 m/s when his chain breaks. he coasts up the hill until he comes to a stop after 3.5 s. find his acceleration while on the hill, and the distance he travelled up the hill.

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Answers (1)

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Booker · Answer 1

1. Answer;

Acceleration is;

-2.46m/s²

Explanation;

The initial velocity is 8.6 m/s, the final velocity = 0 m/s

The time is 3.5 seconds

Using the equation;

V = U + at

but V = 0, - U = at

a = - U/t = - 8.6 / 3.5

= - 2.457 m/s²

= - 2.46 m/s² (2 d. p)

2. Answer;

The distance is;

=15.1 m

Solution;

a = - 2.46 m/s², v=0 and U = 8.6 m/s

Using the equation;

V² = U² + 2as (where s is the distance)

but v = 0, thus, s = U²/2a

= - 8.6² / 2 (-2.46)

= - 73.96 / -4.92

= 15.1 m (1 d. p)