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2 March, 11:03

ball is dropped from a height of 1.60 m and rebounds to a height of 1.20 m. Approximately how many rebounds will the ball make before losing 90% of its energy?

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  1. 2 March, 11:14
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    the ball rebounds 8 times before losing 90% of its energy

    Explanation:

    given information:

    height, h₁ = 1.6 m

    rebound height, h₂ = 1.2 m

    energy loss = 90% = 0.9

    first we can calculate the loss energy after the rebound

    energy loss = 1 - [ (height of rebound/height of the ball) ^n

    where

    n = number of the bounce

    energy loss = 1 - (h₂/h₁) ^n

    0.9 = 1 - (1.2/1.6) ^n

    (0.75) ^n = 1 - 0.9

    n log 0.75 = log 0.1

    n = log 0.1/log 0.75

    = 8 bounces
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