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4 June, 14:58

The front of a 1300 kg car is designed to absorb the shock of a collision by having a "crumple zone" in which the front 1.20 m of the car collapses in absorbing the shock of a collision. (a) If a car traveling 29.0 m/s stops uniformly in 1.20 m, how long does the collision last

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  1. 4 June, 15:13
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    The collision last 0.83 s

    Explanation:

    Using the equation of motion,

    S = (v+u) t/2 ... Equation 1

    making t the subject of the equation,

    t = 2S / (v+u) ... Equation 2

    Where S = distance, v = final velocity, u = initial velocity, t = time

    Given: v = 0 m/s, u = 29.0 m/s, S = 1.20 m,

    Substituting these values into equation 2

    t = 2 (1.2) / (29+0)

    t = 2.4/29

    t = 0.83 sec.

    Thus the collision last 0.83 s
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