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30 July, 14:24

You measure the power delivered by a battery to be 5.83 W when it is connected in series with two equal resistors. How much power will the same battery deliver if the resistors are now connected in parallel across it

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  1. 30 July, 14:28
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    P = 23.32 W

    Explanation:

    In series

    equivalent Resistance

    R (eq) = R+R=2R

    In parallel equivalent resistance

    R (eq) = R*R / (R+R) = R/2

    since.

    power

    P=V² / R

    in series

    ⇒V = √ (P*R)

    =√ (5.83*2R)

    =√ (11.66R)

    in parallel

    P = V² / R (eq)

    = (√ (11.66R) ²) / (R/2)

    P=11.66 * R * 2/R

    P = 23.32 W
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