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13 May, 05:29

A 3.0 kilogram object is thrown upward with an initial speed of 10 meters per second. what maximum height will the object reach?

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  1. 13 May, 05:55
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    Time = v*sintheta/g = 10*1/9.8 = 1.02s therefore h=1/2*9.8 * (1.02) ^2 = 5.10m
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