A 50 kg crate is pulled across the ice by a rope that is angled at 30 degrees above the horizontal. If the tension in the rope is 100 newtons, what is the magnitude of the "lifting" and "pulling" components of the force in the rope?

Question

Bailey Terry

Physics

27 January, 01:21

A 50 kg crate is pulled across the ice by a rope that is angled at 30 degrees above the horizontal. If the tension in the rope is 100 newtons, what is the magnitude of the "lifting" and "pulling" components of the force in the rope?

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Answers (1)

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Emely Blair · Answer 1

Let:

Vx = the pulling component of force

Vy = the lifting component of force

Vy:

Sin (n°) = Vy/hypotenuse

hypotenuse * Sin (n°) = Vy

100N*sin (30°) = Vy

50N = Vy

Vx:

Cos (n°) = Vx/hypotenuse

Hypotenuse * cos (n°) = Vx

100N*cos (30°) = Vx

about 86.6N = Vx